6
$\begingroup$

Consider the binary variables $x, y, z \in \{0,1\}$.

I'd like to formulate the two if-then constraints:

$$ x + y \geq 2 \implies z = 0, \tag{1} $$ $$ x + y \leq 1 \implies z = 1. \tag{2} $$

Constraint (1) can be formulated as

$$ x + y \leq 2 - z. $$

How to proceed for (2) ?

$\endgroup$

2 Answers 2

9
$\begingroup$

Indeed, for the first constraint you can use: $$ x+y+z \le 2 $$

For the second one, it might be easier to model the contraposition: $$ z=0 \quad \Rightarrow \quad x+y \ge 2 \quad \Rightarrow \quad x=y=1 $$

This yields: $$ 1-z \le x \\ 1-z \le y $$

$\endgroup$
5
$\begingroup$

You want to linearize $xy=1-z$. See https://or.stackexchange.com/a/473/500 for a somewhat automatic derivation of a linearization for $xy=z$ via conjunctive normal form. You can then replace $z$ with $1-z$ in the resulting constraints.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.