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Dec 9, 2022 at 21:17 comment added prubin Full row rank might require that you first insert slacks and surpluses. For instance, you might want to say $a'x \le b_1$ and $a'x \ge b_2$ (same $a$ both places). That creates an initial $A$ matrix (before slacks) with row rank less than the number of rows. You get full rank after expanding the matrix.
Dec 9, 2022 at 19:06 comment added prubin Seems plausible, but plausible $\neq$ proven. :-)
Dec 9, 2022 at 18:39 comment added Krypt This is interesting! So maybe we can safely say that dual also has extreme points if primal has finite optimum and the primal constraint matrix has linearly independent rows?
Dec 9, 2022 at 18:34 history answered prubin CC BY-SA 4.0